For diagram number 9, we compute
$$ \begin{align} \chi_d^a\equiv{1\over 2} \sum_{kcl} \langle kl\vert V\vert cd\rangle t_{kl}^{ac} \tag{34} \end{align} $$at a cost of \( A^2 n_u^3 \) and then compute
$$ \begin{align} P(ab)\sum_d \chi_d^a t_{ij}^{db} \tag{35} \end{align} $$at the cost of \( A^3 n_u^3 \).